Selesaikan lah Soal Invers Berikut ini

y = 2x + 1 / x - 3 => y(x-3) = 2x+1
xy -3y = 2x+1 => xy - 2x = 3y + 1 (pindah ruas)
x(y-2) = 3y + 1
x = 3y + 1 / y - 2
invers f = 3x + 1 / x - 2
f-1 (x+1) = 3(x+1) +1 / (x+1)-2
= 3x + 4 / x-1  (D)