Tolong bantuin yaa Hasil dari integral 4x-3/√(6x-4x²)² dx

[tex] \int\limits { \frac{4x-3}{ \sqrt{ 6x-4x^{2} } }} \, dx [/tex]
= [tex]\int\limits { (4x-3) (6x-4x^{2})^{- \frac{1}{2} } \, dx[/tex]
= [tex]\int\limits { \frac{(4x-3) (6x-4x^{2})^{- \frac{1}{2} } \, d(6x-4x^{2})}{6-8x} [/tex]
= [tex]\int\limits { - \frac{1}{2} (6x-4x^{2})^{- \frac{1}{2} } \, d(6x-4x^{2})[/tex]
= [tex]- (6x-4x^{2})^{\frac{1}{2}}+c[/tex]
maaf kalo salah (-/\-)