tolong dijawab kk beserta caranya

f(x) = 2(x)^(-1) mk f'(x) = - 2(x)^(-2) = - 2/x²
Krn f'(x) selalu bernilai negatif, mk gradien grs singgung selalu negatif
a) x=2 mk y=2/2=1
m1 = f'(1)= 2/1² = 2
Grs singgung : y-y1=m1(x-x1)
y-1 = 2(x-2)
y=2x-3
Grs normal : m2= - (1/m1) = - ½
y-y1 = m2(x-x1)
y-1 = - ½(x-2)
y = - ½x + 2

b) y = - 1 mk - 1 = 2/x atau x = - 2
m1=f'(-2)=2/(-2)²=½
Grs singgung : y-y1=m(x-x1)
y+1=½(x+2)
y=½x
Grs normal : m2= -1/m1 = -1/(½) = - 2
y-y1=m2(x-x1)
y+1= - 2(x+2)
y = -2x-5