Matematika

Pertanyaan

diketahui vektor p=3 -6 -2 vektor q=2 -2 x dan vektor r=4 -2 3.jika vektor p tegak lurus dengan vektor q hasil p-2q+3r=

1 Jawaban

  • P = (3,-6,-2)
    Q = (2,-2,x)
    R = (4,-2,3)
    P tegak lurus Q
    Ditanya: P - 2Q + 3R

    P • Q = 0
    (3 × 2) + (-6 × -2) + (-2 × x) = 0
    6 + 12 - 2x = 0
    18 = 2x
    9 = x

    P - 2Q + 3R
    = (3,-6,-2) - 2(2,-2,9) + 3(4,-2,3)
    = (3,-6,-2) - (4,-4,18) + (12,-6,9)
    = (-1,-2,-20) + (12,-6,9)
    = (11,-8,-11)

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