jika 3log2=a dan 2log7=b maka 6log147=........

Bab Logaritma
Matematika SMA Kelas X

6log 147
= ²log 147 / ²log 6
= (²log (7² x 3)) / (²log (2 x 3))
= (²log 7² + ²log 3) / (²log 2 + ²log 3)
= (2 . b + 1/a) : (1 + 1/a)
= (2ab + 1)/a : (a + 1)/a
= (2ab + 1) / (a + 1)