Diketahui vektor p=(2,-3) vektor q=(1,-1) vektor r=(-2,4) Hitunglah panjang vektor p-2q+r

p=(2,-3)
q=(1,-1)
r=(-2,4)
p-2q+r=(2-2-2,-3+2+4)
=(-2,3)
|p-2q+r|=√((-2)²+(3)²)
=√13

Vektor

p ( 2, -3)
q = (1, 1)
r = (-2,4)

misal S = p - 2q + r

sx = (2)  -2(1) + (-2)  = 2 - 2 - 2 = - 2
sy = (-3) - 2(-1) +(4) = -3 +2 + 4 = 3
S(x,y) = (-2, 3)

| S | = √(x²+y²) = √(4 +9) = √13