Matematika

Pertanyaan

tolong di jwb yg ada pd gambar yh..
tolong di jwb yg ada pd gambar yh..

1 Jawaban

  • 2.
    PQ = 13
    SQ = 5
    maka PS^2 = 13^2 - 5^2
    PS^2= 169 - 25
    PS^2 = 144
    PS = akar 144
    PS = 12
    maka luas segitiga PQR = 1/2 × a × t
    = 1/2 × 15 × 12
    = 90 cm^2

    3.
    PR^2 = 16^2 + 12^2
    PR^2 = 256 + 144
    PR^2 = 400
    PR = akar 400
    PR = 20 cm

    4.
    (4x)^2 + (3x)^2 = 5^2
    16x^2 + 9x^2 = 25
    25x^2 = 25
    x^2 = 25/25
    x^2 = 1
    x = akar 1
    x = 1
    d1 = PR = 2 × PT = 2 × 4 = 8
    d2 = SQ = 2 × QT = 2 × 3 = 6
    luas = 1/2 × d1 × d2
    = 1/2 × 6 × 8
    = 24 cm^2