sebuah balok mempunyai perbandingan ukuran panjang : lebar : tinggi = 4 : 3 : 2. jika luas permukaan balok tersebut 468 cm , tentukan ukuran panjang, lebar, tin

panjang = 4x
lebar = 3x
tinggi = 2x

Lp = 2(p.l + p.t + l.t)
468 = 2(4x.3x + 4x.2x + 3x.2x)
468/2 = 12x^2 + 8x^2 + 6x^2
234 = 26x^2
x^2 = 234/26
x^2 = 9
x = √9
x = 3

panjang = 4x = 4(3) = 12 cm
lebar = 3x = 3(3) = 9 cm
tinggi = 2x = 2(3) = 6 cm

468 = 2(4x*3x + 4x*2x + 3x*2x)
468 = 2(12x^2 + 8x^2 + 6x^2)
468 = 2(26x^2)
468 = 52x^2
9 = x^2
3 = x

panjang = 4×3 = 12cm
lebar = 3×3= 9cm
tinggi = 2×3= 6cm