Harap bantuannya tentang bab turunan pertama

f(x) = x^2 (2x + 3)^3 = u . v
u = x^2 => u' = 2x
v = (2x + 3)^3 => v' = 3(2x + 3)^2 . 2 = 6(2x + 3)^2
f'(x) = u' v + v' u
f'(x) = 2x (2x + 3)^3 + 6(2x + 3)^2 . x^2
f'(1) = 2(1) (2.1 + 3)^3 + 6(2.1 + 3)^2 . 1^2
= 2 (5)^3 + 6 . (5)^2 . 1
= 2(125) + 6(25)
= 250 + 150
= 400