persamaan garis sejajar.garisnya. :2x+3y+6:0. melalui titik (-2,5)adalah

m = -x/y = -2/3
y-y1 = m(x-x1)
y-5 = -2/3(x+2)
3y-15 = -2x - 4
3y + 2x = 11
3y + 2x - 11 = 0

Mohon maaf apabila ada kesalahan

2x + 3y + 6 = 0
3y = -2x - 6 ( : 3)
y = -2/3x - 2

m = -2/3
y-y1 = m (x - x1)
y - 5 = -2/3 ( x - (-2))
y - 5 = -2/3 (x + 2)
y - 5 = -2/3x + 4/3 (×3)
3y - 15 = -2x + 4
3y + 2x - 19 = 0