tolong bantuin pake cara

13. dik:
m=10 kg
∆T=75-25=50°C
Q=4×10^5 J
dit:
c?
dij:
Q=m.c.∆T
4×10^5=10.c.50
4x10^5=500c
c=800 j/kg°c (D)
14. dik
∆t=200-50=150
Q=1050J
dit:
C?
dij:
C=Q/∆T
C=7j/°c (A)

13.) m = 10 kg
ΔT = T₂ - T₁ = 75 - 25 = 50 °C
Q = 4 × 10⁵ J

c = Q/m.ΔT
c = 4 × 10⁵/10.50
c = 4 × 10⁵/500
c = 800 J/kg °C <= Jawaban D ✓

14.) ΔT = T₂ - T₁ = 200 - 50 = 150 °C
Q = 1050 J

C = Q/ΔT
C = 1050/150
C = 7 J/°C <= Jawaban A ✓