suatu basa m(oh)2 mempunyai ksp 4x10^-12 berapa ph larutan jenuh basa tersebut?

Ksp M(OH)2 = [M2+][OH-]^2
4 × 10^-12 = (s)(2s)^2
4 × 10^-12 = 4s^3
s^3 = 10^-12
s = 10^-4
[OH-] = 10^-4
pOH = -log[OH-]
pOH = -log(10^-4)
pOH = 4
pH = 14-4 = 10