Tentukan derajat keasaman (pH) larutanm NH4OH 0,01 M ( Kb = 10-5) sama caranya yaa kakak ^^

[OH-] = √(Kb × M)
[OH-] = √(10^-5 × 0,01)
[OH-] = √(10^-7)
[OH-] = 10^-3,5
pOH = -log[OH-]
pOH = -log10^-3,5
pOH = 3,5
pH = pKw - pOH
pH = 14 - 3,5
pH = 10,5

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