tolong bantuanya yaaa kakak

Misalkan:
volume kerucut awal : V1
volume kerucut setelah diperbesar : V2
diameter kerucut awal : d1
diameter kerucut diperbesar 3 kali : d2
tinggi kerucut awal : t1
tinggi kerucut diperbesar 2 kali : t2

Maka, didapat perbandingan:

V1/V2 = (1/3*1/4*π*d1*d1*t1) : (1/3*1/4*π*d2*d2*t2

27/V2 = (d1*d1*t1) / (d2*d2*t2)
27/V2 = (d1^2*t1) / (2d1*2d1*3t1)
27/V2 = (d1^2*t1) / (4d1^2*3t1)
27/V2 = (d1^2*t1) / (12*d1^2*t1)
27/V2 = 1 / 12
V2 = 27 * 12
V2 = 324

Maka, volume kerucut tersebut adalah 324 cm^3 (B).

v = 1/3πdt
   = 1/3π x 2d x 3t
   = 6 x 1/3πdt
   = 6 x 27 
   = 162