tentukan pH larutan dari A. 100 Ml larutan as klorida (hci) 0,01 M B. Larutan kalsium hidroksida (Ca(OH)2) 0,005 M

A. 100 ml larutan asam klorida (HCl) 0,01 M
[H+] = M × valensi asam = 0,01 × 1 = 0,01 = 10^-2
pH = -log[H+]
pH = -log10^-2
pH = 2
B. Larutan kalsium hidroksida (Ca(OH)2) 0,005 M
[OH-] = M × valensi basa
[OH-] = 0,005 × 2
[OH-] = 0,1 = 10^-1
pOH = -log[OH-]
pOH = -log10^-1
pOH = 1
pH = 14 - pOH = 14 - 1 = 13