diketahui 2log 3 = a dan 3log 5 =b. nilai 6log 40 = ....

Bab Logaritma
Matematika SMA Kelas X

6log 40
= (3log 40) / (3log 6)
= (3log (5 x 2^3)) / (3log (3 x 2))
= (3log 5 + 3log (2^3)) / (3log 3 + 3log 2)
= (3log 5 + 3 . 3log 2) / (1 + 3log 2)
= (b + 3/a) : (1 + 3/a)
= (ab + 3)/a : (a + 3)/a
= (ab + 3) / (a + 3)