apabila diketahui larutan KOH 0,02 M, maka pH larutan tsb adalah (log 2= 0,3)

KOH --> K⁺ + OH⁻
OH⁻ = 0,02 M

POH = -log (OH⁻)
POH = -log (0,02)
POH = -log (2 x 10⁻²)
POH = 2 - log2

PH + POH = 14
PH + (2 - log2) = 14
PH = 14 - (2 - log2)
PH = 12 + log2
PH = 12 + 0,3
PH = 12,3