Sebuah dadu dilempar dua kali. Peluang munculnya bilangan genap, bila diketahui telah muncul bilangan prima adalah

n(S) = 36

n(A) = {(2, 2), (2, 4) ,(2, 6), (3, 2), (3, 4), (3,6), (5, 2), (5 4), (5, 6)} = 9

P(A) = n(A)/n(S)

=9/36

= 1/4

langsung aja yy

n(s) = 36

n(a) = {(22) , (23) , (24) , (25), (26) , (34) , (54) , (63) , (65)} = 9

p(a) = n(a) / n(s) = 9/36 = ¼

semoga berguna +_+