Matematika

Pertanyaan

limit x mendekati 3/2 phi sinx+1/cos^2x =

1 Jawaban

  • Limit trigonometri

    lim (x-> 3/2 π)  (sin x + 1) / cos² x
    lim (x-> 3/2 π)  (1+sin x) / (1 - sin² x)
    lim (x -> 3/2 π)  (1 + sin x) / (1 +sin x )(1- sin x)
    lim (x-> 3/2π)  1/(1- sin x)
    x = 3/2π 
    limit = 1/ ( 1  - sin (3/2π) = 1 / ( 1- (-1)) = 1 / (1+1)  = 1/2

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