rumus fungsi f(x) = ax+b. jika f(2) = 13 dan f(5) = 22 adalah....

f(x)= ax+b
f(2)= a.2+b=13
f(5)= a.5+b=22 -
-----------------------
a (-3) = -9
a = 3
b=> f(2)= 3.2+b =13
=6+b=13
=b=13-6
=b=7

f(2) = 2a + b = 13
f(5) = 5a + b = 22

dgn proses eliminasi menghasil kan
3a = 9
a = 9/3
a = 3

f (2) = 2(3) + b = 13
6 + b. = 13
b. = 13 - 6
b = 7
jadi rumus fungsi nya
f(x) = 3x + 7