diketahui balok ABCD. EFGH dengan panjang AB=(3✖+2)cm,BC=14 cm, dan CG=15 cm. jika luas permukaan balok tersebut 1.580 cm²,volume balok ABCD. EFGH adalah....cm³

AB = 3x + 2
p = 3x + 2

BC = 14
l = 14

CG = 15
t = 15

L = 1.580
2×(pl + pt + lt) = 1.580
pl+pt+lt = 1.580/2
(3x+2)×14 + (3x+2)×15 + 14×15 = 790
(3x+2)×29 + 210 = 790
(3x+2)×29 = 790-210 = 580
(3x+2) = 580/29 = 20
3x + 2 = 20
panjang = 20 cm

V = 20×14×15 = 4.200 cm^3

smg mmbantu