Rumus fungsi f(x+1)=2x-3 ,g(x)=X²-2x-1,h(x)=1-x.Rumus komposisi (g•h•f)(x)=? Mau tanya Gimana caranya??

f(x+1)=2x-3
misl t=x+1
x=t-1
f(t)=2(t-1)-3
f(t)=2t-2-3
f(x)=2x-5

g(x)=x^2-2x-1
h(x)=1-x
(gohof)(x)=g(h(f(x)))
=g(h(2x-5)
=g(1-(2x-5))
=(2x-4)^2-2(2x-4)-1
=4x^2-16x+16-4x+8-1
=4x^2-20x+23
hnya mncba