• a. [tex] \frac{\ \textless \ AOB}{\ \textless \ COD} = \frac{busur AB}{busur CD} \\ \\ \frac{45 derajat}{90 derajat} = \frac{AB}{11} \\ \\ \frac{1}{2} = \frac{AB}{11} \\ \\ AB = \frac{11}{2} = 5,5 cm [/tex]

    b. [tex]panjang busur AB = \frac{45 derajat}{360 derajat} X keliling lingkaran \\ \\ 5,5 = \frac{1}{8} X \frac{22}{7} X 2 X r \\ \\ r = \frac{5,5 X 8 X 7}{22 X 2} \\ \\ r = \frac{308}{44} \\ \\ r = 7 cm[/tex]

    c. [tex]Luas juring COD = \frac{90}{360} X \frac{22}{7} X 7 X 7 \\ \\ = \frac{1}{4} X \frac{22}{7} X 7 X 7 \\ \\ = 38,5 cm^{2} [/tex]

    d. [tex]Luas juring AOB = \frac{45}{360}X \frac{22}{7} X 7 X 7 \\ \\ = \frac{1}{8} X \frac{22}{7} X 7 X 7 \\ \\ = 19,25 cm^{2} [/tex]

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