tolong bantu no.9 dan 10 ya mohon bantuan kalian
Matematika
sijago2
Pertanyaan
tolong bantu no.9 dan 10 ya mohon bantuan kalian
2 Jawaban
-
1. Jawaban arsetpopeye
9) luas = 144
(2y)(2y) = 144
4y^2 = 144
y^2 = 36
y = √36 = 6
Jadi s = 2y = 2(6) = 12 cm
Keliling = 4s = 4(12) = 48 cm
10) p : l = 3 : 1 => p/l = 3/1 => p = 3l
Luas = 300
p.l = 300
3l.l = 300
l^2 = 300/3
l = √100 = 10 => p = 3l = 3(10) = 30
Keliling = 2(p + l) = 2(30 + 10) = 2(40) = 80 cm -
2. Jawaban Machzen
9.
Sisi :
√144m= 12m
Keliling :
4 x sisi
4 x 12cm
48cm
10.
3x · x= 300cm²
3x² = 300cm²
x = 100cm²
x = √100cm
x = 10cm
Panjang = 3 x 10cm= 30cm
Lebar = 1 x 10cm = 10cm
Keliling persegi panjang :
2 x (p+l)
2 x (30cm + 10cm)
2 x 40cm
80cm