Matematika

Pertanyaan

tolong bantu no.9 dan 10 ya mohon bantuan kalian
tolong bantu no.9 dan 10 ya mohon bantuan kalian

2 Jawaban

  • 9) luas = 144
    (2y)(2y) = 144
    4y^2 = 144
    y^2 = 36
    y = √36 = 6
    Jadi s = 2y = 2(6) = 12 cm
    Keliling = 4s = 4(12) = 48 cm

    10) p : l = 3 : 1 => p/l = 3/1 => p = 3l
    Luas = 300
    p.l = 300
    3l.l = 300
    l^2 = 300/3
    l = √100 = 10 => p = 3l = 3(10) = 30

    Keliling = 2(p + l) = 2(30 + 10) = 2(40) = 80 cm
  • 9.
    Sisi :
    √144m= 12m
    Keliling :
    4 x sisi
    4 x 12cm
    48cm

    10.
    3x · x= 300cm²
    3x² = 300cm²
    x = 100cm²
    x = √100cm
    x = 10cm

    Panjang = 3 x 10cm= 30cm
    Lebar = 1 x 10cm = 10cm

    Keliling persegi panjang :
    2 x (p+l)
    2 x (30cm + 10cm)
    2 x 40cm
    80cm