Please nomor 9 sama 10 pake cara
Matematika
fawwazhangtuah2
Pertanyaan
Please nomor 9 sama 10 pake cara
2 Jawaban
-
1. Jawaban Iruchi
9
(8x - 20) + (4x + 8) = 180
12x - 12 = 180
12x = 192
x = 16
pelurus AOC = COB
COB = 4x + 8 = 4.16 + 8 = 72 derajat
10
(6x + 4) + (5x + 9) = 90
11x + 13 = 90
11x = 77
x = 7
penyiku AQC = CQB
CQB = 5x + 9 = 5.7 + 9 = 44 derajat -
2. Jawaban elmaulana
Jawab :
9]
Diketahui,
∠AOC = [8x - 20]°
∠BOC = [4x + 8]°
Cari nilai 'x'
∠AOB + ∠BOC = 180°
[8x - 20]° + [4x + 8]° = 180°
12x - 12° = 180°
12x = 180° + 12°
12x = 192°
x = 192° ÷ 12°
x = 16°
Hasil penerjemahan,
∠AOC = [8x - 20]°
∠AOC = [8.16 - 20]°
∠AOC = 128° - 20°
∠AOC = 108°
Jadi, besar pelurus untuk ∠AOC adalah 180° - 108° = 72° [D]
10]
Diketahui,
∠AQC = [6x + 4]°
∠BQC = [5x + 9]°
Cari nilai 'x'
∠AQC + ∠BQC = 90°
[6x + 4]° + [5x + 9]° = 90°
11x + 13° = 90°
11x = 90° - 13°
11x = 77°
x = 7°
Hasil penerjemahan,
∠AQC = [6x + 4]°
∠AQC = [6.7 + 4]°
∠AQC = 42° + 4°
∠AQC = 46°
Jadi, besar penyiku untuk ∠AQC adalah 90° - 46° = 44° [B]
Semoga membantu ^_^