Matematika

Pertanyaan

Please nomor 9 sama 10 pake cara
Please nomor 9 sama 10 pake cara

2 Jawaban

  • 9
    (8x - 20) + (4x + 8) = 180
    12x - 12 = 180
    12x = 192
    x = 16

    pelurus AOC = COB
    COB = 4x + 8 = 4.16 + 8 = 72 derajat

    10
    (6x + 4) + (5x + 9) = 90
    11x + 13 = 90
    11x = 77
    x = 7

    penyiku AQC = CQB
    CQB = 5x + 9 = 5.7 + 9 = 44 derajat
  • Jawab :

    9]
    Diketahui,
    ∠AOC = [8x - 20]°
    ∠BOC = [4x + 8]°
     
    Cari nilai 'x'
    ∠AOB + ∠BOC = 180°
    [8x - 20]° + [4x + 8]° = 180°
    12x - 12° = 180°
    12x = 180° + 12°
    12x = 192°
    x = 192° ÷ 12°
    x = 16°

    Hasil penerjemahan,
    ∠AOC = [8x - 20]°
    ∠AOC = [8.16 - 20]°
    ∠AOC = 128° - 20°
    ∠AOC = 108°

    Jadi, besar pelurus untuk ∠AOC adalah 180° - 108° = 72° [D]

    10]
    Diketahui,
    ∠AQC = [6x + 4]°
    ∠BQC = [5x + 9]°

    Cari nilai 'x'
    ∠AQC + ∠BQC = 90°
    [6x + 4]° + [5x + 9]° = 90°
    11x + 13° = 90°
    11x = 90° - 13°
    11x = 77°
    x = 7°

    Hasil penerjemahan,
    ∠AQC = [6x + 4]°
    ∠AQC = [6.7 + 4]°
    ∠AQC = 42° + 4°
    ∠AQC = 46°

    Jadi, besar penyiku untuk ∠AQC adalah 90° - 46° = 44° [B]

    Semoga membantu ^_^