persamaan bayangan kurva y=4x^2 + 4x - 1 0leh dilatasi dengan puisat (0,0) dan faktor skala 2 di lanjutkan translasi T=-3,-1 adalah ...

y = 4x^2+4x-1 pusat (0,0) skala 2
(x,y)-->(x',y')
x' = kx y'=ky
x' = 2x y'=2y
x'/2 = x y'/2=y
substitusi
y = 4x^2+4x-1
y'/2 = 4(x'/2)^2+4(x'/2)-1
y'/2 = 4(x'^2/4)+4x'/2-1
y'/2 =x'^2+2x'-1
y' = 2x'^2+4x'-2 <=> y = 2x^2+4x-2

lanjut translasi (-3,-1)
(x,y)-->(x',y')
x' = x+(-3) y' = y+(-1)
x' = x-3 y' = y-1
x'+3 = x y'+1 = y

substitusi
y = 2x^2+4x-2
y'+1 = 2(x'+3)^2+4(x'+3)-2
y' = 2(x'^2+6x'+9)+4x'+12-2-1
y' = 2x'^2+12x'+18+4x'+12-2-1
y' = 2x'^2+16x'+27
y = 2x^2+16x+27