nilai minimum fungsi objectif Z=3x=4y sisitem persamaan 2x + 3y≥12, 5x+2y≥19 ;x≥0; y≥0 adalah

pakai sistem eliminasi
2x+3y = 12 |x2| 4x+6y=24
5x+2y = 19 |x3| 15x+6y=57
-11x = -33
x = 3
2x+3y = 12
2.3+3y= 12
6+3y =12
3y =12-6
3y =6
y = 2
Fungsi objectif Z=3x+4y
= 3.3 + 4.2
= 9 + 8
= 17