(64)^⅔-(125)^⅓+(243)^¹/5 =
Matematika
Aldianputrianti
Pertanyaan
(64)^⅔-(125)^⅓+(243)^¹/5 =
2 Jawaban
-
1. Jawaban BillNabila
(64)^⅔-(125)^⅓+(243)^¹/5
==>> ³√64² - ³√125 + ^5√243
==>> ³√4096 - 5 + 3
==>> 16-5+3 = 14 -
2. Jawaban Anonyme
Bab Bilangan Berpangkat
Matematika SMP Kelas IX
(64)^(2/3) - (125)^(1/3) + (243)^(1/5)
= 4² - 5 + 3
= 16 - 2
= 14