Matematika

Pertanyaan

(64)^⅔-(125)^⅓+(243)^¹/5 =

2 Jawaban

  • (64)^⅔-(125)^⅓+(243)^¹/5
    ==>> ³√64² - ³√125 + ^5√243
    ==>> ³√4096 - 5 + 3
    ==>> 16-5+3 = 14
  • Bab Bilangan Berpangkat
    Matematika SMP Kelas IX

    (64)^(2/3) - (125)^(1/3) + (243)^(1/5)
    = 4² - 5 + 3
    = 16 - 2
    = 14

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