tolong bantuannya nomor 4
Fisika
nisa4521
Pertanyaan
tolong bantuannya nomor 4
2 Jawaban
-
1. Jawaban chenle
5 cm^2 = 0,0005 m^2
P (tekanan) = F/A
= 8/0,0005
= 16.000 Pa -
2. Jawaban cingcang
F = 8 N
A = 5 cm² = 5×10^-4 m²
P = __
P = F / A
P = 8 / 5×10^-4
P = 1,6×10^4 Pa ← jwb