vektor dot product u = [4, -4, 4] v = [0, 1, 0] w= [-1, -2, 1] hitung a) (u x v) - (v x w) b) (u x v) - w

((4×0)+((-4)×1)+(4×0)) - ((0×(-1))+(1×-2)+(0×1))
(-4)-(-2)
-4+2=-2==>jwbn a
((4×0)+((-4)×1)+(4×0))-(-1,-2,1)
(-4)-(-1,-2,1)==>jwbn b , udh smpe gini doang
kalo misalnya soalnya kyk gini
(u × v) - |w| jwbnya
((4×0)+((-4)×1)+(4×0)) - ((-1)^2+(-2)^2+(1)^2)
(-4)-(1+4+1)
(-4)-6=2

vektor dot product

a)
(u . v) - (v . w)
= (4.0 + (-4.1) + 4.0) - (0(-1) + 1(-2) + 0.1)
= (0 + (-4) + 0) - (0 + (-2) + 0)
= -4 -(-2)
= -4 + 2
= -2

b)
(u.v) - w
= -4 - (-1 -2 1)
= -4 + (1 2 -1)