Nilai maksimum dari fungsi f(x)=16x²+112x-111

f'(x) = 0 syarat maks/mins
32x + 112 = 0
32x = -112
x = -112/32
x = -7/2

fmaks = f(-7/2) = 16×(-7/2)^2 + 112×7/2 - 111 = 16×49/4 + 56×7 - 111 = 4×49 + 392 - 111 = 196 + 281 = 477

smga mmbantu