³log108-³log12+³log6-³log2 adalah?
Matematika
nurhayaty1
Pertanyaan
³log108-³log12+³log6-³log2 adalah?
2 Jawaban
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1. Jawaban cindysanobia
3 log 108 : 3 log 12 = 9
3 log 6 : 3 log 2 = 3
9.3 = 27 -
2. Jawaban msandyka
Tentukan [tex]\log_{3} {108} - \log_{3} {12} + \log_{3} {6} - \log_{3} {2}[/tex]
[tex]\log_{3} {108} - \log_{3} {12} + \log_{3} {6} - \log_{3} {2} = \log_{3} {108} + \log_{3} {6} - \log_{3} {12} - \log_{3} {2} \\ \log_{3} {108} - \log_{3} {12} + \log_{3} {6} - \log_{3} {2} = \log_{3} {(108)(6)} - (\log_{3} {12} + \log_{3} {2}) \\ \log_{3} {108} - \log_{3} {12} + \log_{3} {6} - \log_{3} {2} = \log_{3} {(108)(6)} - (\log_{3} {(12)(2)} \\ \log_{3} {108} - \log_{3} {12} + \log_{3} {6} - \log_{3} {2} = \log_{3} {\frac{(108)(6)}{(12)(2)}[/tex]
[tex]\log_{3} {108} - \log_{3} {12} + \log_{3} {6} - \log_{3} {2} = \log_{3} {27} \\ \log_{3} {108} - \log_{3} {12} + \log_{3} {6} - \log_{3} {2} = \log_{3} {3^{3}} \\ \log_{3} {108} - \log_{3} {12} + \log_{3} {6} - \log_{3} {2} = 3[/tex]