Matematika

Pertanyaan

dik:f(x)=2x+3 ,g(x)=x+2,h(x)=3x+2 tentukan berapa hogof (2)x gohof 3 +fogoh 2

1 Jawaban

  • --menentukan (hogof)(2)—

    (hog)(x) = h(g(x))

                    = h(x+2)

                    = 3(x+2)+2

                    = 3x+6+2

                    = 3x+8

    (hogof)(x) = (hog)(f(x))

                    = (hog)(2x+3)

                    = 3(2x+3)+8

                    = 6x+9+8

                    = 6x+17

    (hogof)(2) = 6x+17

                    = 6(2)+17

                    = 12+17

                    = 29

    --menentukan (gohof)(3)—

    (goh)(x) = g(h(x))

                    = g(3x+2)

                    = (3x+2)+2

                    = 3x+4

    (gohof)(x) = (goh)(f(x))

                    = (goh)(2x+3)

                    = 3(2x+3)+4

                    = 6x+9+4

                    = 6x+13

    (gohof)(3) = 6x+13

                    = 6(3)+13

                    = 18+13

                    = 31

     

    --menentukan (fogoh)(2)—

    (fog)(x) = f(g(x))

                    = f(x+2)

                    = 2(x+2)+3

                    = 2x+4+3

                    = 2x+7

    (fogoh)(x) = (fog)(h(x))

                    = (fog)(3x+2)

                    = 2(3x+2)+7

                    = 6x+4+7

                    =6x+11

    (fogoh)(2) = 6x+11

                    = 6(2)+11

                    = 12+11

                    = 23

    Maka nilai (hogof)(2)x(gohof(3)+(fogoh)(2)

    = 29 x 31+23

    = 899+23

    = 922




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