cari invers y=5+(x-2)/(2x-3)

langsung aja yy

y = 5 + (x-2) / (2x-3)

y (2x-3) = 5 + x - 2

2xy - 3y = 3 + x

2xy - x = 3 + 3y

x(2y -1) = 3(y+1)

x = 3 (y + 1) / (2y - 1)

maka

f`¹(y) = 3 (y + 1) / (2y - 1)

f`¹(x) = 3 (x + 1) / (2x - 1)

semoga berguna +_+