Matematika

Pertanyaan

Jika p-q= cosA dan [tex] \sqrt{2pq} [/tex]= sinA maka p²+q²=

2 Jawaban

  • p-q= cosA
    p^2 + q^2 - 2pq = cos^2 A

    akar(2pq) = sin A
    2pq = sin^2 A

    p^2 + q^2 - 2pq + 2pq = cos^2 A + sin^2 A
    p^2 + q^2 = 1
  • Trigonometri

    √(2pq) = sin A
    [ √(2pq) ]² = sin² A
    2pq  = sin² A

    p - q = cos A
    (p-q)² = cos² A

    p² + q²  = cos² A + 2 pq
    p² + q² = cos² A  + sin² A
    p² + q² = 1

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