Jika p-q= cosA dan [tex] \sqrt{2pq} [/tex]= sinA maka p²+q²=
Matematika
rinalova
Pertanyaan
Jika p-q= cosA dan [tex] \sqrt{2pq} [/tex]= sinA maka p²+q²=
2 Jawaban
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1. Jawaban Iruchi
p-q= cosA
p^2 + q^2 - 2pq = cos^2 A
akar(2pq) = sin A
2pq = sin^2 A
p^2 + q^2 - 2pq + 2pq = cos^2 A + sin^2 A
p^2 + q^2 = 1 -
2. Jawaban DB45
Trigonometri
√(2pq) = sin A
[ √(2pq) ]² = sin² A
2pq = sin² A
p - q = cos A
(p-q)² = cos² A
p² + q² = cos² A + 2 pq
p² + q² = cos² A + sin² A
p² + q² = 1