tolong dijawab ya yang nomor 40, 44, dan, 46 pakai caranya ya

40. Llayang = [tex] \frac{d1×d2}{2} [/tex]
Llayang = [tex] \frac{8×12}{2} [/tex]
Llayang = 8×6
Llayang = 48

44. Diket = PR = 52 cm
TR = 12 cm
QS = 18 cm
dit. = Kel.layang = ?
Jawab = ST = QS÷2
ST = 18 cm÷2
ST = 9 cm

QR = ST
QR = 9 cm

PT = PR - TR
PT = 52 cm - 12 cm
PT = 40 cm

Untuk mencari PS dan SR kita gunakan pythagoras
PS = √(PT²+ST²)
PS = √(40²+9²) cm
PS = √(1600+81) cm
PS = √1681 cm
PS = 41 cm

PQ = PS
PQ = 41 cm

SR = √(ST²+TR²) cm
SR = √(9²+12²) cm
SR = √(81+144) cm
SR = √225 cm
SR = 15 cm

QR = SR
QR = 15 cm

Kel.layang = PS+SR+QR+PQ
Kel.layang = 41 cm+15 cm+15 cm+41 cm
Kel.layang = 112 cm

Maaf, no.46 saya tidak tahu