Diberikan tiga buah titik A(6,3,3), B(3,9,-12), C(5,5,10). Jika AD=2AC-BC, maka koordinat titik D adalah

A = (6,3,3)
B = (3,9,-12)
C = (5,5,10)
AD = 2AC - BC
Ditanya: D

AC = vektor C - vektor A
AC = (5,5,10) - (6,3,3)
AC = (-1,2,7)

2AC = 2(-1,2,7)
2AC = (-2,4,14)

BC = vektor C - vektor B
BC = (5,5,10) - (3,9,-12)
BC = (2,-4,22)

AD = (-2,4,14) - (2,-4,22)
vektor D - vektor A = (-2,4,14) - (2,-4,22)
vektor D - (6,3,3) = (-2,4,14) - (2,-4,22)
vektor D - (6,3,3) = (-4,8,-8)
vektor D = (-4,8,-8) + (6,3,3)
vektor D = (2,11,-5)