fungsi f,g dan h ditentukan oleh f(x)=(1/2x-8,g(x)=2x+10 dan h(x)=x²-2x+1 , rumus hofof adalah?

(hofof) = (h(f(f(x))))
=> h(f(1/2x-8))
=> h(1/2(1/2x-8)-8)
=> h(1/4x-4)-8
=> h(1/4x-12)
=> (1/4x-12)"2 - 2(1/4x-12) + 1
=> 1/6x"2 -6x+144 - 1/2x +24 +1
=> 1/6x"2- 13/2x +169

semoga bermanfaat!