bantu kawan. diketahui persamaan kuadrat x^2-9×-12=0, dengan akar-akar p dan q. nilai p^2+q^2=

x^2 - 9x - 12 = 0
a=1
b= -9
c= -12
akar akar p dan q
p + q = -b/a = -(-9) / 1 = 9/1 = 9
p.q = c/a = -12 / 1 = -12
p^2+q^2 =?
(p+q)(p+q)-2pq = (9.9)-2(-12)
p^2+2pq+q^2-2pq = 81 + 24
p^2+q^2 = 105