Sudut p = 30,panjang pq =20 dan panjang pr =60,hitunglah luas segitiga pqr?

L = 1/2 (20) (60) sin 30
= 600 (1/2)
= 300

Luas segitiga

ΔPQR
∠P = 30°
PQ = 20
PR = 60

tinggi = t
sin P = t/PR --> t = PR. sin P

Luas = 1/2 (alas)(tinggi) = 1/2 ((PQ)(PR)(sin 30)
L = 1/2 (20)(60)(1/2)
L = 10(30)
L  =300 satuan