diketahui 3log2=a dan 2log7=b. tentukan nilai 14log81

Diketahui:
³log2 = a ---------->> ²log3 = 1/a
²log7 = b

Ditanya:
¹⁴log81 = ??

Jawab:
¹⁴log81
= (log81)/(log14)
= (log3⁴)/(log7.2)
= (4.log3)/(log7 + log2)
= (4.1/a)/(b + 1)
= (4/a)/(b + 1)
= (4)/(ab + a)