Matematika

Pertanyaan

integral sin 2x cos X DX =?

1 Jawaban

  • int sin(2x) cosx dx
    = int 2 sinx cosx cosx dx
    = int 2 sinx cos²x dx
    u = cosx → du = -sinx dx
    = int (-2 u²) du
    = -(2/3)u³ + c
    = -(2/3)cos³x + c

Pertanyaan Lainnya