yg bisa tolong bantu jawab no.3&4 ya+caranya. Makasih:) GBu

3. AB = BC = CD = AD = s
Keliling = 4s
60 = 4s
s = 60/4
s = 15 cm

s^2 = (1/2 AC)^2 + (1/2 BD)^2
15^2 = (1/2 AC)^2 + (1/2 × 18)^2
225 = (1/2 AC)^2 + 81
(1/2 AC)^2 = 225 - 81
1/2 AC = √144
AC = 12 × 2
AC = 24 cm

4. a) PR^2 = QR^2 - PQ^2
PR^2 = 20^2 - 16^2
PR^2 = 400 - 256
PR = √144
PR = 12 cm

PT^2 = PR^2 + TR^2
PT^2 = 12^2 + 28^2
PT^2 = 144 + 784
PT = √928
PT = 2√232 cm

b) Segitiga TPQ tidak siku-siku di Q, tetapi siku-siku di P
QT^2 = PQ^2 + PT^2
QT^2 = 16^2 + √928^2
QT^2 = 256 + 928
QT^2 = 1.184
QT = √1.184 cm
QT = 2√296 cm

langsung aja yy

3.
karna sebangun
K = 4s
60 = 4s
15 = s

maka
s² = (½AC)² + (½BD)²

15² = (½AC)² + (½×18)²

(½AC)² = 225 - 81

½AC = √144

AC = 12 × 2

AC = 24

semoga berguna +_+